Determine the common point of the lines 2x+y-5=0 and -3x+4y-9=0.

To determine the crossing point of the 2 lines, we have to
solve the system formed from their equations:

2x+y=5
(1)

-3x+4y=9 (2)

We'll
multiply the relation (1) by 3 and the relation (2), by 2, and after that, we'll add (1)
to (2). We'll obtain:

6x+3y-6x+8y = 15 +
18

After reducing similar terms, we'll
get:

11y = 33

y =
33/11

y=3

We'll
substitute y by 3, into the relation (1):

2x+3 =
5

2x = 5-3

2x =
2

x =
1

The crossing point is A
(1,3).