i) Solve the simultaneous equations 4x + 3y + 4 = 0, 3x Could you please teach me step by step, so that I can understand easily...

The given simultaneous equations
are:

4x + 3y + 4 = 0   ...   
(1)

3x - 12y + 22 = 0   ...
(2)

Multiplying equation (1) by 4 we
get:

16x + 12y + 16 = 0   ...   
(3)

adding equation (2) and (3) we
get:

3x + 16x - 12y + 12y + 22 + 16 =
0

19x + 38 = 0

19x =
-38

Therefore:

x = -38/19 =
-2

Substituting this value of x in equation (1) we
get:

4*(-2) + 3y + 4 = 0

-8 +
3y + 4 =0

3y =
4

Therefore:

y =
4/3

Answer:

x = -2, and y =
4/3