Find the slope and y-intercept of the line given by y = 5x + 4 . Find the coordinates of a point, other than ( 0 , b ) on the line.

Any line of the form y = mx+c  is  a straight line  which 
has a slope m and it makes an intercept of C on y axis.

The
given line ,  y= 5x+c  has a slope 5 and it intercepts y axis at 4 units anbove the
origin.

Slope 5 means the line is inclined x degrees and
tanx = 5.

Also we can get the y intercept by putting x =0
in y = 5x+4: y = 5*0+4 =4. Or (0,4) is a point on y
=5x+4.

To get a point other than (0,4) 0n y = 5x+4. Let the
x coordinate be 1, the y = 5*1+4 = 9. So (1,9) is a point other than
(0,b)

Let y = 0, then fron y=5x+4 becomes, 0= 5x+4 , or x =
-4/5. So, (4/5,0) is another point on the line. And 4/5 is the X intercept of the line
on X axis.