There are 2 numbers whose sum is 53. 3 times the smaller number is equal to 19 more than the larger number. Which are the numbers?

assume that the fsmaller number =S and the larger number is=L

then, S+L= 53....... (1)

3 times the smaller number = 19 more than the larger number

==> 3 S = 19 + L ........ (2)

Now, combining equation (1) and (2) we have:

S+L = 53

3S = 19  + L ==> L = 3S -19

substitute in eqution (1),

 S + (3S- 19) = 53

 4S - 19 = 53

4S = 72     divide by 4

S = 72/4 = 18

and L = 3(18)- 19 = 35